rupees 18000 for 2 whole no. 1 upon 2 years at 10% per annum compounded annually
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Given Principal= P= 18000
Rate of interest Per Annum= i = 10%
Time = n = 2 1/2 = 2.5 years
Lets do it two parts 2 years and half year
Compounded Amount = P(1+i)^n = 18000(1+10/100)^2
= 18000(1 + 0.1)^2
=18000(1.1)^2
=18000(1.21)
= 21780..
For remaining half year ..Rate of interest will be = 10%/2 =5% ..period will be 1
= 21780(1+5/100)^1
= 21780(1 + 0.05)
=21780(1.05)
=22869
Rate of interest Per Annum= i = 10%
Time = n = 2 1/2 = 2.5 years
Lets do it two parts 2 years and half year
Compounded Amount = P(1+i)^n = 18000(1+10/100)^2
= 18000(1 + 0.1)^2
=18000(1.1)^2
=18000(1.21)
= 21780..
For remaining half year ..Rate of interest will be = 10%/2 =5% ..period will be 1
= 21780(1+5/100)^1
= 21780(1 + 0.05)
=21780(1.05)
=22869
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