Math, asked by proveen, 5 months ago

Rupees 20000 amounts to Rupees 25000 at a certain rate of interest per annum. In what time will rupees 5528 amount to rupees 11056 at the same rate?

Answers

Answered by Anonymous

$In \: 8 \: years, \: Rs. \: 5528 will amount to Rs. 11056 at the same rate (12.5%)Given :Rs.20000 amounts to = Rs 25000In = 2 yearsTo find :Time in which Rs. 5528 amount to Rs. 11056 at the same rate of interest.Solution :Case IWe need to find the Rate of interest.Here,Principal (P) = Rs.20000Amount = Rs.25000Time (T) = 2 years. SI = Amount - PrincipalSimple Interest (SI) = Rs.5000We know that,Case IIWe have to find the time.Here,Principal (P) = Rs. 5528Amount = Rs.11056Rate (R) = 12.5 % (from above)SI = Amount - PrincipalWe know that,In 8 years, Rs. 5528 will amount to Rs. 11056 at the same rate (12.5%)$

Answered by Anonymous

Answer:

In 8 years, Rs. 5528 will amount to Rs. 11056 at the same rate (12.5%)

Given :

Rs.20000 amounts to = Rs 25000

In = 2 years

To find :

Time in which Rs. 5528 amount to Rs. 11056 at the same rate of interest.

Solution :

Case I

We need to find the Rate of interest.

Here,

Principal (P) = Rs.20000

Amount = Rs.25000

Time (T) = 2 years.

SI = Amount - Principal

⇒25000−20000

⇒5000

Simple Interest (SI) = Rs.5000

We know that,

SI = Principal × Rate× Time/100

⟹ 5000 = 20000 × 2 × R/100

⟹ 5000× 100 = 40000× R

⟹500000=40000×R

⟹R=500000/ 40000

⟹ R = 50/4

⟹ Rate = 12.5%

Case II

We have to find the time.

Here,

Principal (P) = Rs. 5528

Amount = Rs.11056

Rate (R) = 12.5 % (from above)

SI = Amount - Principal

⇒11056−5528

⇒5528

We know that,

SI= Principal×Rate×Time/100

⟹5528= 5528×12.5×t / 100

⟹5528×100=69100×T

⟹552800=69100×T

⟹T= 552800/ 69100

⟹T=8

⟹ time = 8 years

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