Rupees 3600 is divided into two parts such that interest of one part at 5% per annum for 3 years in equal to the interest of second part at 25/4% per annum for 4 years. Find the amount of the parts?
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Divide Rs. 3,600 into two parts such that if one part be lent at 9% per annum and the other at 10% per annum, the total annual income is Rs. 333.
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Let Rs.3600 be divided into two parts x and y respectively.
x+y=3600
y=3600−x
As we know that,
S.I.=
100
P×R×t
Now,
For Rs.x,
Rate of interest =9% per annum
t=1
S.I.=
100
x×9×1
For Rs.y,
Rate of interest =10% per annum
t=1
S.I.=
100
y×10×1
⇒S.I.=
100
(3600−x)×10
Now, according to the question-
100
9x
+
100
10(3600−x)
=333
⇒9x+36000−10x=33300
⇒x=36000−33300=2700
Therefore,
y=3600−2700=900
Hence Rs.3600 can be divided in Rs.2700 and Rs.900 respectively.
Answer:
Let Rs.3600 be divided into two parts x and y respectively.
x+y=3600
y=3600−x
As we know that,
S.I.=
100
P×R×t
Now,
For Rs.x,
Rate of interest =9% per annum
t=1
S.I.=
100
x×9×1
For Rs.y,
Rate of interest =10% per annum
t=1
S.I.=
100
y×10×1
⇒S.I.=
100
(3600−x)×10
Now, according to the question-
100
9x
+
100
10(3600−x)
=333
⇒9x+36000−10x=33300
⇒x=36000−33300=2700
Therefore,
y=3600−2700=900
Hence Rs.3600 can be divided in Rs.2700 and Rs.900 respectively.