Question

rupees 40000 in 3 year at 15/2 percent per annum​

Answer 1

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Answer 2

Step-by-step explanation:

$compound \: interest \: = ci \\ \\ ci = (p(1 + \frac{r}{100} ) {}^{2} - 1) \\ \\ ci = (40000(1 + \frac{7.5}{100} ) {}^{2} - 1) \\ \\ ci = (40000( \frac{107.5}{100} ) {}^{2} - 1) \\ \\ ci = (40000(1.75) {}^{2} - 1) \\ \\ ci = (40000(3.625) - 1) \\ \\ ci = (40000(2.625)) \\ \\ ci = 105000 \\ \\ hope \: this \: helpful \: to \: you \: follow \: me \:$