Math, asked by agneeb07, 10 months ago

Rupees 41.75 was paid as the interest on rupees 835 at 26/4% per annum. If the date of lending was 5 January 2009, find the date up to which the interest was paid.

Answers

Answered by rambabu083155
1

Answer:

The date up to which the interest was paid 8 September 2009.

Step-by-step explanation:

Given,

S.I = Rs 41.75

Principal ( P ) = Rs 835

Rate ( R ) = 26/4 %

Date of Lending = 5 January 2009

We know that:

⇒  S.I =

⇒  Rs 41.75  =

⇒ T =

⇒ T = years

⇒ T = month

⇒ T = 9 months 3 days

So, The date up to which the interest was paid

= 5 January 2009 + 9 months 3 days

= 8 September 2009

Answered by amitnrw
1

Up to 12th Oct , 2009 interest was paid if Rs 41.75 was paid as the interest on Rs 835 at 26/4% per annum. and date of lending was 5 January 2009

Given:

  • P= Rs 835
  • Interest = 41.75
  • R = 26/4  = 13/2 % per annum
  • Date of Lending 5 Jan 2009

To Find:

  • Date up to which interest was paid

Solution:

SI = P * R * T /100

SI = Simple Interest

Step 1 :

Solve for T by substituting given values

41.75 = 835 x (13/2) x T /100

=> T = 10/13 Years

Step 2 :

Find number of days by multiplying with 365 ( as 1 year = 365 days)

365 x 10/13 ≈ 281 Days

Step 3 :

Add 281 Days in 5 Jan 2009

Jan = 27 , Feb = 28 , Mar = 31 , Apr 30,  May 31, Jun 30 , Jul 31 , Aug 31 , Sep 30 , Oct 12

Up to 12th Oct , 2009 interest was paid.

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