Math, asked by gauravshar8010, 1 year ago

Rupees 6500 were divided equally among a certain number of persons. Had there been 15 more persons, each would have got rupees 30 less. Find the original number of persons.

Answers

Answered by Kusumsahu7
8

Let the number of persons be 'x'.

Let the amount of money each person got be 'y'

According to question

6500/x=y  ........................(1)

and 6500/x+15=y-30

6500=xy-30x+15y-450

6500=6500-30x+15y-450 ........................using(1)

30x-15y+450=0

Dividing throughout by 15

2x-y+30=0

2x-6500/x+30=0 ........................using(1)

2x2-6500+30x=0

Dividing throughout  by 2

x2-15x+3250=0

x2-65x+50x+3250=0

x(x-65)+50(x-65)=0

(x+50)(x-65)=0

therefore x=65

putting x=65 in (1)

6500/65=y

y=100


gauravshar8010: thanks for the answer ..
Kusumsahu7: Well come bro
aishwaryarao47: but we got x = 50 bro
gauravshar8010: yes
Answered by singhnikhiljbp
1

Answer:

Step-by-step explanation:

Let the number of persons be 'x'.

Let the amount of money each person got be 'y'

According to question

6500/x=y  ........................(1)

and 6500/x+15=y-30

6500=xy-30x+15y-450

6500=6500-30x+15y-450 ........................using(1)

30x-15y+450=0

Dividing throughout by 15

2x-y+30=0

2x-6500/x+30=0 ........................using(1)

2x2-6500+30x=0

Dividing throughout  by 2

x2-15x+3250=0

x2-65x+50x+3250=0

x(x-65)+50(x-65)=0

(x+50)(x-65)=0

therefore x=65

putting x=65 in (1)

6500/65=y

y=1

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