Math, asked by AMANuchiha, 10 months ago

Rupesh had 2 sons. He had some chocolates which he distributed among them. To his elder son, he gave 3 chocolates more than half the number of chocolates with him. To his younger son he gave 4 chocolates more than one fourth of the remaining number of chocolates with him. He was left with 11 chocolates. How many chocolates did he initially have?​

Answers

Answered by aayushi890
3

Step-by-step explanation:

(11+4)*4/3= 20

(20+4) *3/2 = 36

(36+3)*2/1 =78

ans=78 chocolates

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