Rupesh had 2 sons. He had some chocolates which he distributed among them. To his elder son, he gave 3 chocolates more than half the number of chocolates with him. To his younger son he gave 4 chocolates more than one fourth of the remaining number of chocolates with him. He was left with 11 chocolates. How many chocolates did he initially have?
Answers
Answer:
33 chocolates
Step-by-step explanation:
let the total number of chocolates with him be x.
To his elder son he gave chocolates=(x/2)+3=(x+6)/3
To his younger son he gave chocolates=[x-(x+6/3)]/4 +4=(3x-x-6/3)/4 + 4
=2(x-3)/12 + 4
=(x-3)/6 + 4
=(x-3+24)/6=(x+21)/6
Total chocolates=> x= (x+6)/3 + (x+21)/6 + 11
=> x=(2x+12+x+21+66)/6
=> x=(3x+99)/6
=> x=3(x+33)/6
=> x=(x+33)/2
=>2x= x+33
=> 2x-x=33
=> x= 33
So,Rupesh has a total of 33 chocolates.