Question

Rupesh had 2 sons. He had some chocolates which he distributed among them. To his elder son, he gave 3 chocolates more than half the number of chocolates with him. To his younger son he gave 4 chocolates more than one fourth of the remaining number of chocolates with him. He was left with 11 chocolates. How many chocolates did he initially have?​

Answer 1

Answer:

33 chocolates

Step-by-step explanation:

let the total number of chocolates with him be x.

To his elder son he gave chocolates=(x/2)+3=(x+6)/3

To his younger son he gave chocolates=[x-(x+6/3)]/4 +4=(3x-x-6/3)/4 + 4

                                                                 =2(x-3)/12 + 4

                                                                 =(x-3)/6 + 4

                                                                 =(x-3+24)/6=(x+21)/6

Total chocolates=> x= (x+6)/3 + (x+21)/6 + 11

                           => x=(2x+12+x+21+66)/6

                           => x=(3x+99)/6

                           => x=3(x+33)/6

                           => x=(x+33)/2

                           =>2x= x+33

                           => 2x-x=33

                           => x= 33

So,Rupesh has a total of 33 chocolates.