Math, asked by Liberal789, 1 day ago

Rupinder has a total of Rs 12 in coins of denominations 50 paise ,

20 paise , and 10 paise. The number of 50 paise coins is four times the

number of 20 paise coins. The total number of coins is 35. How many coins of each domination does he have???​

Answers

Answered by ArnavKrishna24
3

Answer:

No. of 20 paise coins = 5

No. of 50 paise coins = 20

Number of 10 paise coins = 10

Step-by-step explanation:

Let the number of 20 paise coins = x

Total value = 1200 paise

Number of 50 paise coins = 4x

Number of 10 paise coins = 35 - 5x

Ratio of number of coins:

x: 4x: (35 - 5x)

Ratio by value:

20x : 200x: (350 - 50x)

220x + 350 - 50x = 1200

170x = 1200 - 350 = 850

x = 850/170 = 5

No. of 20 paise coins = x = 5

No. of 50 paise coins = 4x = 20

Number of 10 paise coins = 35 - 5x = 10

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