Question

Ruth had 85, 88, 78, and 81 on her first four tests in Math. What must she get in the fifth test to have an average of 85?

Answer 1

Answer:

93

Step-by-step explanation:

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Answer 2

Answer:

93

Step-by-step explanation:

Let us take it as x

Average of 5 numbers = $\frac{n1 + n2+n3+n4+n5}{5}$

Given :-

n1 = 85

n2 = 88

n3 = 78

n4 = 81

n5 = x

Average = 85

$\frac{85+88+78+81+x}{5}$ = 85

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85+88+78+81+x = 5 × 85

332 + x = 425

x = 425 - 332

x  = 93

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