Ruthy and Sylvia work together for 15 days and 20 days respectively. If they worked together for 6 days, then the remaining work by them is
(please help me it is very important for me)
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Remaining work from Ruthy is 9 Remaining work from Sylvia is 14 days
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Answer:
Given A can do the work in 20 days and B can do it 15 days.
Then work done by A in one day =
20
1
And, work by B in one day =
15
1
Then, the work done by A & B in one day =
20
1
+
15
1
=
60
7
A & B done 6 days together then work done in A & B in 6 days =
60
7
×6=
10
7
Then friction of work left =1−
10
7
=
10
3
Then B can do
10
3
work =
10
3
×
1
15
=
2
9
=4
2
1
days.
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