Question

Ruthy and Sylvia work together for 15 days and 20 days respectively. If they worked together for 6 days, then the remaining work by them is



(please help me it is very important for me) ​

Answer 1

Remaining work from Ruthy is 9 Remaining work from Sylvia is 14 days

Answer 2

Answer:

Given A can do the work in 20 days and B can do it 15 days.

Then work done by A in one day =

20

1

And, work by B in one day =

15

1

Then, the work done by A & B in one day =

20

1

+

15

1

=

60

7

A & B done 6 days together then work done in A & B in 6 days =

60

7

×6=

10

7

Then friction of work left =1−

10

7

=

10

3

Then B can do

10

3

work =

10

3

×

1

15

=

2

9

=4

2

1

days.