Math, asked by samruddhi2646, 5 months ago

Rutionalize
the denominator
12/4√3-√2​

Answers

Answered by Bhosale2002
1

Answer:

 \frac{12 \sqrt{3} + 3 \sqrt{2}  }{11}

Step-by-step explanation:

 \frac{12}{4 \sqrt{3}  -  \sqrt{2} }

we can multiplying Numerator and Denomenator by

 4 \sqrt{3 }  +  \sqrt{2}

 =  \frac{12 \times( 4 \sqrt{3} +  \sqrt{2} ) }{(4 \sqrt{3}  - 2)(4 \sqrt{3 }  +  \sqrt{2}) }

 =  \frac{48 \sqrt{3} + 12 \sqrt{2}  }{48 - 4}

 =  \frac{48 \sqrt{3}  + 12 \sqrt{2} }{44}

 =  \frac{12 \sqrt{3} + 3 \sqrt{2}  }{11}

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