Math, asked by KLikhi, 7 months ago

Ryan age is 4 times that of Ranger. 3 years back, Ryan was 5 times as old as Ranger . What are their present ages? 

Answers

Answered by MaIeficent
8

Step-by-step explanation:

Given:-

  • Age of Ryan is 4 times as that of Ranger.

  • 3 years ago, Ryan was 5 times as old as Ranger.

To Find:-

  • The present ages of Ryan are Ranger.

Solution:-

Let the present age of Ranger be x

As, Ryan is 4 times as old as Ranger.

Present age of Ranger = 4x

3 years ago:-

Age of Ranger = x - 3

Age of Ryan = 4x - 3

Given, Ryan was 5 times as old as Ranger.

 \sf \implies4x - 3 = 5(x - 3)

 \sf \implies4x - 3 = 5x - 15

 \sf \implies5x - 4x = 15 - 3

 \sf \implies x  =  12

▪︎ x = 12

▪︎ 4x = 12 × 4 = 48

We have:-

  • x = 12

  • 4x = 48

Therefore:-

Present age of Ryan = 48 years

Present age of Ranger = 12 years

Answered by viny10
13

Step-by-step explanation:

Given:-

Age of Ryan is 4 times as that of Ranger.

3 years ago, Ryan was 5 times as old as Ranger.

To Find:-

  • The present ages of Ryan are Ranger.

Solution:-

Let the present age of Ranger be x

As, Ryan is 4 times as old as Ranger.

Present age of Ranger = 4x

3 years ago:-

  • Age of Ranger = x - 3

  • Age of Ryan = 4x - 3

Given, Ryan was 5 times as old as Ranger.

4x−3=5(x−3)

4x−3=5x−15

5x−4x=15−3

x=12

▪︎ x = 12

▪︎ 4x = 12 × 4 = 48

We have:-

  • x = 12

  • 4x = 48

Therefore:-

Present age of Ryan = 48 years

Present age of Ranger = 12 years

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