Question

s=1/2!-2/3!+3/4!-....n-1/n! solution in java it's from Nested loop please help. I need the answer fast ​

Answer 1

Required Answer:-

Question:

Write a program in Java to find the sum of the series.

S = 1/2! - 2/3! + 3/4! - 4/5! +...

Solution:

Here is the program.

1. import java.util.*;
2. public class Sum {
3. public static void main(String[] args) {
4. int n;
5. double f=2.0;
6. double s=0.0;
7. Scanner sc=new Scanner(System.in);
8. System.out.print("Enter limit - ");
9. n=sc.nextInt();
10. for(int i=1,c=3;i<=n;i++,c++)
11. {
12. if(i%2==1)
13. s+=i/f;
14. else
15. s-=i/f;
16. f * =c;
17. }
18. System.out.println("Sum is: "+s);
19. sc.close();
20. }
21. }

Explanation:

• We will create a loop that iterates n times. Inside the loop, we will calculate the sum of the series. First term of the series is added and the next term is subtracted. This continues upto n terms. Here, the control variable is 'i'. If the value of 'i' is odd, then the term of the series is added else it's subtracted.

Output is attached.