Question

S=1/2+2/3+3/4+....to n terms

Answer 1

HELLO THERE!

Here's the program code in JAVA:

I'm using Scanner class to input the value of n from the user..

import java.util.*;

class Series

{

public static void main (String args[])

{

Scanner sc = new Scanner (System.in);

int n;

double sum = 0.0;

System.out.print("Enter the number of terms: ");

n = sc.nextInt();

for (int i = 1; i <= n; i++)

{

sum = sum + (i/(i+1));

}

System.out.println("Sum of the series is: " + sum);

}

}

THANKS!

Answer 2

Here is the answer :

Code

import java.util.*;

class Sum_series

{

public static void main(String[] args)

{

double i, s = 0.0;

int n;

Scanner sc = new Scanner(System.in);

System.out.print("Enter the last number: ");

n = sc.nextInt();

for(i = 1.0; i < n; i++)

{

s=s+ (i*1.0)/(i + 1.0);

}

System.out.println("sum="+s);

}

}

Working :

• The i-loop starts from 1.0 then increases by 1.0 each time
• It goes on until n-1
• The printing is done by s such that s = i/(i+1.0)
• Well this prints the sum of 1/2+2/3.............

Hope it helps you

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