Math, asked by dixi0303, 11 months ago

S
[1 + 2tanx(secx + tanx)]dx = .......... +C,
(A) log|secx(secx - tanx)
(B)log|tanx(secx + tanx)
(C)log|cosecx(secx - tanx)|
(D)log|secx(secx + tanx)|

Answers

Answered by vikashsharma45

0

Answer:

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