Physics, asked by Anonymous, 8 months ago

ɪғ ᴀ ᴄᴀʀ ᴄᴏᴠᴇʀs 1/4ᴛʜ ᴏғ ᴛʜᴇ ᴛᴏᴛᴀʟ ᴅɪsᴛᴀɴᴄᴇ ᴡɪᴛʜ sᴘᴇᴇᴅ ᴠ1 ᴀɴᴅ ɴᴇxᴛ ʜᴀʟғ ᴏғ ᴛᴏᴛᴀʟ ᴅɪsᴛᴀɴᴄᴇ ᴡɪᴛʜ sᴘᴇᴇᴅ ᴠ2 ᴀɴᴅ ᴛʜᴇ ʀᴇᴍᴀɪɴɪɴɢ ᴅɪsᴛᴀɴᴄᴇ ᴡɪᴛʜ sᴘᴇᴇᴅ ᴠ3 . ғɪɴᴅ ᴛʜᴇ ᴀᴠᴇʀᴀɢᴇ sᴘᴇᴇᴅ.

Answers

Answered by EnchantedGirl
26

GIVEN:- A car covers 1/4 th distance with speed v1 , 1/4th distance with V2 & Another 1/4 th distance with V3.

REQUIRED TO FIND :- The average speed.

FORMULAS USED :-

\boxed{Avg\: Speed = Total\: Distance/  Total \: Time}

\boxed{Time = Distance / velocity }

SOLUTION

》AVERAGE SPEED = TOTAL DISTANCE / TOTAL TIME

= S/2 + S/4 + S/4 / d1/v1 + d2/V2 + d3/v3

= S / S/2v1 + S/4V2 + S/4V3

= 1 / 1/2V1 + 1/4V2 + 1/4V3

= 4V1.V2.V3 / 2V2V3 + V1V3 + V1V2.

》\boxed{ Hence, Average \:  speed = 4v1v2v3 \:   \div 2v</u></em></strong><strong><em><u>2</u></em></strong><strong><em><u>v3 \:  + v1v3 \:  + v1v2}

HOPE IT HELPS :)

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