s=1÷a+3÷a^3+5÷a^5+.......+n
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Answer:
Run a loop from 1 to n and get the i-th term of the series by calculating term = (i / ai). Sum all the generated terms which is the final answer.
Explanation:
# Python 3 program to find the sum of
# the given series
import math
# Function to return the
# sum of the series
def getSum(a, n):
# variable to store the answer
sum = 0;
for i in range (1, n + 1):
# Math.pow(x, y) returns x^y
sum += (i / math.pow(a, i));
return sum;
# Driver code
a = 3; n = 3;
# Print the sum of the series
print(getSum(a, n));
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