Question

s=1/t^2 - 1/t.Find velocity and acceleration.In differentiation​

Answer 1

hey mate.

given here

s=1/t^2. - 1/t

find here

velocity (v)= ds/dt=?

acceleration dv/dt=(a)A=?

now,

v=ds/dt=d/dt(1/t^2. - 1/t

=-2(t)^-3 - (-1)(t)^-2

=-2t^-3+t^-2

again,

dv/dt=d/dt(-2t^-3 +. t^-2)

=(-2)(-3)t^-4. +. (-2) t^-3

=6t^-4. - 2t^-3

I hopes its helps u.

@abhi.