Question

s
17) A car moving on a straight highway with speed 35" is brought
to stop within a distance of 200m. What is the retardation of
the car?​

Answer 1

Answer:

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Answer 2

$\text{\underline{\underline{\large{Given}}}}$

• A car moving on a straight highway with speed 35" is brought to stop within a distance of 200m.

Here we get,

Initial speed of the car, u = 35 ms^(-1)

Final speed of the car, v =0

$\text{\large{\orange{TO\:Find}}}$

• The retardation of the car. (Let the retardation be a)

$\text{\purple{\underline{\large{Solution!}}}}$

$\mathcal{\blue{\boxed{v{}^{2} = u {}^{2} + 2as}}}$

$0 = (35) {}^{2} + 2a × 200 \\ a = – (35 \times 35)/(2 \times 200) \\ a= {– 3.06 ms}^{ - 2}$

$\sf{\boxed{\green{Hence\:the\:retardation\:of\:the\:car\:is\: { - 3.06}^{ - 2} }}}$

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