Question

s^2+2s+1 solve this question​

Answer 1

Step-by-step explanation:

Adding 1 has completed the left hand side into a perfect square :

s2-2s+1 =

(s-1) • (s-1) =

(s-1)2

Things which are equal to the same thing are also equal to one another. Since

s2-2s+1 = 0 and

s2-2s+1 = (s-1)2

then, according to the law of transitivity,

(s-1)2 = 0

We'll refer to this Equation as Eq. #3.2.1

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

(s-1)2 is

(s-1)2/2 =

(s-1)1 =

s-1

Now, applying the Square Root Principle to Eq. #3.2.1 we get:

s-1 = √ 0

Add 1 to both sides to obtain:

s = 1 + √ 0

The square root of zero is zero

This quadratic equation has one solution only. That's because adding zero is the same as subtracting zero.

The solution is:

s = 1

Answer 2

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Step-by-step explanation:

Adding 1 has completed the left hand side into a perfect square :

s2-2s+1 =

(s-1) • (s-1) =

(s-1)2

Things which are equal to the same thing are also equal to one another. Since

s2-2s+1 = 0 and

s2-2s+1 = (s-1)2

then, according to the law of transitivity,

(s-1)2 = 0

We'll refer to this Equation as Eq. #3.2.1

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

(s-1)2 is

(s-1)2/2 =

(s-1)1 =

s-1

Now, applying the Square Root Principle to Eq. #3.2.1 we get:

s-1 = √ 0

Add 1 to both sides to obtain:

s = 1 + √ 0

The square root of zero is zero

This quadratic equation has one solution only. That's because adding zero is the same as subtracting zero.

The solution is:

s = 1

$\huge\mathcal{\fcolorbox{lime}{black}{\pink{Hope it's help u}}}$