Question

s/2 + t/3=6 and s/3 - t/2=1/4. Find the value of x and y by substitution​ ​method.

Answer 1

U have given two equations i.e,

S/2 + t/3 = 6 ............(1)

S/3 - t/2 = 1/4 ............(2)

In equation first take the LCM of 2 and 3 , after than your equation becomes ..

3s + 2t = 36 .......(3)

In equation second again take the LCM of 2 and 3 , after then your equation becomes..

2s - 3t / 6 = 1/4

On cross multiplying

8s - 12t = 6 ........(4)

From equation 3 we will get

S = 36 - 2t / 3

On putting the value of s in equation 4

8 ( 36 - 2t / 3) - 12t = 6

288 - 16t / 3 - 12t = 6

288 - 16t - 36t = 18

288 - 52t = 18

52t = 288 - 18

52t = 270

T = 270/52 = 5.19