Question

(S/2+t/3)(t/3-s/2)
Tell me whether my method is correct or not:
(S/2)(-S/2) (t/3)(t/3)
-s2(square)/4 t2(square)/9

Answer 1

Answer:

Hello !, check your answer,

= $(\frac{s}{2} +\frac{t}{3} ) (\frac{t}{3} -\frac{s}{2} )$

 { using the identity $(a+b)(a-b)= a^{2} -b^{2}$ }

= $(\frac{s} {2} )^{2} -\frac{t}{3} ^{2}$

= $\frac{s^{2} }{4} -\frac{t^{2} }{9}$