Question

S () 2

= + v t at s = displacement,

v

0

= initial velocity,

a = acceleration and

t = time. Check the

dimensional validity of the following equation​

Answer 1

Answer:

Writing the dimensions of either side of the given equation.

LHS=8=displacement=[M

0

LT

0

]

RHS=ut=velocity×time=[M

0

LT

−1

][T]=[M

0

LT

0

]

and

2

1

at

2

=(acceleration)×(time)

2

=[M

0

LT

−2

][T]

2

=[M

0

LT

0

]

As LHS=RHS, formula is dimensionally