Question

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Answer 1

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Given,

AD and BC are perpendiculars of AB.

TO PROVE :CD bisects AB

∠BOC = ∠DOC ( ∴ Vertically opposite angles )

DA = BC

∠B = ∠A = 90°

So, by congruence condition, ΔBOC ≅ ΔOAD

So,

now CO = OD

so, it bisects AB on point ''

OA = OB [ by ]

➖➖➖➖➖➖➖➖➖➖➖➖➖

AAS : Angle-Angle-side

CPCT : Corresponding Parts of Congruent Triangles

Answer 2

\huge\underline\bold\red{AnswEr}AnswEr​

Given,

AD and BC are perpendiculars of AB.

TO PROVE :CD bisects AB

∠BOC = ∠DOC ( ∴ Vertically opposite angles )

DA = BC

∠B = ∠A = 90°

So, by congruence condition, ΔBOC ≅ ΔOAD

So,

now CO = OD

so, it bisects AB on point ''

OA = OB [ by ]

➖➖➖➖➖➖➖➖➖➖➖➖➖

AAS : Angle-Angle-side

CPCT : Corresponding Parts of Congruent Triangles