Question

s=20sin(3.14t-n/2) show a=-(3.14)^2s. where s=displacement t=time a=acceleration​

Answer 1

Answer:

etwewgr

Explanation:

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Answer 2

(d)(5±1)/6

Step-by-step explanation:

Given a quadratic eqn such that,

3 {x}^{2} - 5x + 2 = 03x

2

−5x+2=0

To find the roots.

We have to follow the quadratic formula.

Here, we have,

a = 3

b = -5

c = 2

Therefore, we have,

=> D = (b^2-4ac)

=> D = ((-5)^2-4(3)(2))

=> D = (25 - 24)

=> D = 1

Now, from quadratic formula, we have,

=> x = -b/2a ± √D/2a

Substituting the values, we get,

=> x = -(-5)/2(3) ± √1/2(3)

=> x = 5/6 ± 1/6

=> x = (5±1)/6

=> x = 6/6 and 4/6

=> x = 1 and 2/3

Hence, the correct answer is (d) (5±1)/6.

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