Question

S
37) An observer spots a balloon moving with the wind in a horizontal line at a
height of 105 m from the ground. The angle of elevation of the balloon after
sometime reduces from 60° to 30°. Find the distance travelled by the balloon
during the interval​

Answer 1

Answer:

Step-by-step explanation:

I hope it's correct

Answer 2

Distance traveled by the balloon during the interval is 76.87 m

Step-by-step explanation:

A balloon is at a height of 105 m from the ground.

Angle of elevation of the balloon at point A from point C is 30°.

Balloon traveled x meters from point A to B then angle of elevation of the balloon at B from point C is 60°.

From ΔAEC,

tan30° = $\frac{AE}{EC}$

$\frac{1}{\sqrt{3}}=\frac{105}{EC}$

EC = 105√3 m

EC = x + DC

x + DC = 105√3 ------(1)

From ΔBDC,

tan60° = $\frac{BD}{DC}$

√3 = $\frac{BD}{DC}$

BD = DC(√3)

⇒ DC = $\frac{105}{\sqrt{3} }$ m ≈ 60.62 m

Therefore, from equation (1),

x = 105√3 - 60.62

  = 181.86 - 60.62

  = 121.24 m

Practice more similar problems from https://brainly.in/question/15960456