s=4t³+12t+6 find velocity and acceleration
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Answer:
36i - 12j
36i + 12j
6i + 2j
3i + 6j
3i + 2j
Correct answer: 36i + 12j
Explanation:
To find acceleration at time t, we have to differentiate the position vector twice.
Differentiating the first time gives the velocity:
v(t) = r'(t) = 12t3i + 12tj
Differentiating a second time gives the accelaration:
a(t) = r''(t) = 36t2i + 12j
Plug in t=1 to solve for the final answer:
a(1) = r''(1) = 36i + 12j
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