Соs 6x=32cos ^6x-48cos^4x+18cos^2-1
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"Cos (6x)= 32cos^6 (x) - 48cos^4 (x)+18cos^2 (x) -1
R.H.S. ==> cos (6x) = cos 2 (3x) = 2cos2 (3x) – 1
L.H.S. ==> 32cos6x – 48cos4x + 18cos2
=> 2 (16cos6x – 24cos4x + 9cos2x) – 1
=> 2 (4cos3x – 3cosx) 2 – 1
=> 2cos2 (3x) – 1
L.H.S. = R.H.S.
Hence, Proved
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