Question

s-7t+42=0
s-3t=6
solve the linear equation in two variable by elimination method​ please help do by elimination method only​

Answer 1

Answer:

(-30,-12) is the answer

Step-by-step explanation:

s-7t= -42

s-3t=6

s-7t= -42

- s-3t= 6

-4t= 48

t = -12

s - 3(-12) = 6

s+36 = 6

s= -30

Answer 2

Answer:

t=12. s=42

Step-by-step explanation:

Step-1

Make the equations in standard form

s-7t+42= 0 is the first equation

s-3t-6=0 is the second equation

Step-2

Subtract the second equation from the first equation and before subtracting change the sign of second equation. Therefore second equation becomes -s+3t+6=0. Now subtract

s -7t +42 = 0

-s +3t +6 = 0

------------------------

- 4t +48 = 0

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Step-3

Find the value of t from the equation

- 4t+48 = 0

-4t = -48

t = -48/-4

t = 12

Step-4

By substitute the value of t find s

s - 3t= 6

s-3 (12)= 6

s - 36 =6

s =6+36

S=42