S=8+88+888+.... upto 20 terms
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As look at the series we realize that any given term has the number of digit 8 according to its placement in the series. For instance the 3rd term in the series is made of three 8s and thereby we have 888 in the third place.
Similarly the 20th term will have twenty 8s.
S = (n/2)(a +L) ; where n = number of terms, a = first term and L = last term
Therefore S = (20/2)(8+88888888888888888888)
Hence our answer is 888,888,888,888,888,888,960
Similarly the 20th term will have twenty 8s.
S = (n/2)(a +L) ; where n = number of terms, a = first term and L = last term
Therefore S = (20/2)(8+88888888888888888888)
Hence our answer is 888,888,888,888,888,888,960
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