Question

S A cylindrical of radius 12 centimetres containing water to a depth of 20 CM a spherical iron ball is dropped into the tub and thus the level of the water is raised by 6.75 CM then the radius of the sphere is

Answer 1

$\large\sf\implies\:r\:=\:12\:cm$

$\large\sf\implies \:h\:=\:6.75$

$\large\sf\implies\: volume\:=\: \pi\:r^2\:h$

$\large\sf\implies\:volume\:=\pi\:×12×12×6.75$

$<b><u>But,$

$\large\sf\implies\:volume\:of\:iron\:ball\:=\frac{4}{3}\pi\:r^3$

$<b><u>from (1) and (2)$

$\large\sf\implies\frac{4}{3}\pi\:r^3\:=\pi\:×12×12×6.75$

$\large\sf\implies\:r^3\:=\:12×12×6.75×\:\frac{3}{4}$

$\large\sf\implies\:r^3\:=\:729$

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