s a f e is a rhombus as shown in figure 7 find X Y and Z justify your findings
Answers
Step-by-step explanation:
Given :-
SAFE is a Rhombus and OA = 12 cm and OF=9cm
To find :-
Find the values of x,y and z and justify your answers ?
Solution :-
Given that :
SAFE is a rhombus
OA = 12 cm
OF = 9 cm
AE and SF are two diagonals of the rhombus
We know that
In a rhombus, The diagonals bisect each other.
=> AE = AO + OE
=> AE = 2AO = 2OE
=> AO = OE = AE/2
The value of OE =OA = 9 cm
y = 12 cm
and
SO + OF = SF
=> SF = 2 SO = 2 OF
=> SO = OF = SF/2
The value of SO = OF = 9 cm
x = 9 cm
Now ,
We know that
Diagonals bisect each other at right angle
So , ∆ ASO is a right angled triangle
By Pythagoras theorem
Hypotenuse² = Side² + Side²
=> AS² = AO² + SO²
=> AS² = 12²+9²
=> AS² = 144+81
=> AS² = 225
=> AS = ±√225
=> AS = ±15
Since AC can not be negative.
AS = 15 cm
We know that
All sides are equal in a rhombus
=> AS = SE = EF = FA = 15 cm
z = 15 cm
Answer:-
The value of x = 9 cm
The value of y = 12 cm
The value of z = 15 cm
Used formulae:-
In a rhombus ,
- All sides are equal.
- Digonals bisect each other.
- Diagonals bisect perpendicular bisect each other.
Answer:
x= 9cm ( alternate interior angles are always same)
y= 12 cm ( alternate interior angles are always same)
z= OE²+ OF² = EF
144+81= 225
z= 15 cm