S All lengths are in centimetres. R r Y N P, Q, R and S lie on the circle. PR and QS intersect at Y. PY = 2x and YS = x. so 2x The area of triangle YRS = {x-1) @ The area of triangle YQP = x(x + 1). Р Find the value of x.
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S All lengths are in centimetres. R r Y N P, Q, R and S lie on the circle. PR and QS intersect at Y. PY = 2x and YS = x. so 2x The area of triangle YRS = {x-1) @ The area of triangle YQP = x(x + 1). Р Find the value of x.
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Answer:
4
Step-by-step explanation:
The sides are similar and x can be found out by simply substituting.
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