S and R are points on the circumference of the semicircle described on diameter PQ. if PS= SR and angle SPQ= 56 degree calculate angle PQS and angle PQR
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Answer:
Given:
PS= SR,
∠SPQ = 56°
To Find:
∠PQS and∠ PQR = ?
Solution:
Note: ∠PSQ= 90° (since : A triangle inscribed in a
semi circle is a right triangle)
In Δ SPQ,
∠SPQ + ∠PQS + ∠PSQ = 180° (Angle Sum Property)
56° + ∠PQS + 90° = 180°
⇒ ∠PQS + 146° = 180°
⇒ ∠PQS = 180°- 146°
⇒ ∠PQS=34°
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