Question

S and T are points on sides PR and PQ of ∆pqr such that <P=<RTS.show that ∆RPQ~∆RTS​

Answer 1

Step-by-step explanation:

In △RPQ and △RTS

∠R is common

∠RTS=∠P (Given)

∠PRQ=∠TRS=∠R (Common)

Hence, By AA criterion of similarity, △RPQ∼△RTS [henceproved]

Answer 2

Answer:

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