Question

S and T are points on sides PR and QR of ∆PQR such that angle p= angle RTS. show that ∆RPQ ~∆RTS​

Answer 1

Answer:

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Answer 2

$\huge{\mathfrak{\purple{Question}}}$

Sand T are points on sides PR and QR of PQR such that P=RTS . Show that RPQ - RTS.

$\huge{\mathfrak{\purple{Answer}}}$

In △RPQ and △RTS

∠R is common

∠RTS=∠P (Given)

∠PRQ=∠TRS=∠R (Common)

Hence, By AA criterion of similarity, △RPQ∼△RTS  

Hence proved