Question

S and T are points on sides PR and QR of ∆PQR such that <P = <RTS. Show that.

∆RPQ ~ ∆RTS.​

Answer 1

Answer:

In △RPQ and △RTS

∠R is common

∠RTS=∠P (Given)

∠PRQ=∠TRS=∠R (Common)

Hence, By AA criterion of similarity, △RPQ∼△RTS  [henceproved]

Answer 2

It is Proved XD OK

Bye .. :)