S and T are points on sides PR and QR of ∆ PQR such that P= RTS . Show that ∆ RPQ ~ ∆ RTS
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Answer:
Given,
S and T are point on sides PR and QR of ΔPQR
And ∠P = ∠RTS.
In ΔRPQ and ΔRTS,
∠RTS = ∠QPS (Given)
∠R = ∠R (Common angle)
∴ ΔRPQ ~ ΔRTS (AA similarity criterion)
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