Question

S and T are the point on side pr and qr of traiangle pqr such that angle p = angle rts.....show that ∆ rpq ~ ∆ rts

Answer 1

Here is ur answer...

Answer 2

Answer:

Given, S and T are point on sides PR and QR of ΔPQR

And ∠P = ∠RTS

In ΔRPQ and ΔRTS,

∠RTS = ∠QPS (Given)

∠R = ∠R (Common angle)

∴ ΔRPQ ~ ΔRTS (AA similarity criterion)