Question

S and T are the points on the sides
PR and QR in triangle PQR such that <P=<RTS. Show that triangle RPQ~ ️ RTS.​

Answer 1

Answer: Plz Mark Brainliest

Step-by-step explanation

Given: angleP = angleRTS

To Prove:∆RPQ ~ ∆RTS

Proof: In ∆RPQ and ∆RTS

angle R = angle R. (common)

angle P = angle RTS (Given)

By AA similarity,

∆RPQ ~ ∆RTS

Hence,proved.

Answer 2

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In △RPQ and △RTS  

∠R is common  

∠RTS=∠P (Given)  

∠PRQ=∠TRS=∠R (Common)  

Hence, By AA criterion of similarity, △RPQ∼△RTS

Hence proved