Question

s) Average
marks of 100 students as 9o. If 5 as added to the
marks of each student, what is the new
average ?
90
B) 95
105
500​

Answer 1

Answer:

Number of students (N) = 100

Average marks of students (A) = 90

Let sum of marks of all students be Σx

A = $\frac{\sum x}{N}$

or, 90 = $\frac{\sum x}{100}$

or, Σx = 9000

When 5 marks is added to marks of each student,

New sum of marks (Σx₁) = Σx + 5*100 = 9000 + 500 = 9500

New average (A₁) = $\frac{\sum x_{1}}{N}$

= $\frac{9500}{100}$

= 95

New average = 95

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