Physics, asked by jessly2414, 11 hours ago

s bar of length th and cross-section
5 \times  {10}^{ - 3}
on 2 is supported at its two ends and leaded in The depression observed in the middle is 1.
1.96 \times  {10}^{ - 3} m
when so load of 0.1kg is placed. calculate the younges_modulus of the material.​

Answers

Answered by Kritika25675
2

Explanation:

Data : L = 1 m, b = 5 cm = 5×10−2m.d=0.5cm=5×10−3 m

M=0.1kg,Y=2×1011N/m2

Load , W = Mg = 0.1×9.8=0.98N

The depression (sag) produced in the bar.

δ=W4by(ld)3=0.984(5×10−2)(2×1011).(15×10−3)3

=0.984×1016.(2×102)3=0.98×8×1064×1010=1.96×10−4m=0.196mm

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