Question

s chand class 10 physics page no 39 que 18​

Answer 1

Explanation:

hey

a)

I) in series

ii) in parallel

b)

I)0.4 amp

ii)1.8 amp

Answer 2

Dear Student,

Given:

R1=5Ω

R2=10Ω

EMF=6V

A)

To get minimum current, the two resistors should be connected in series.

To get maximum current, we should connect the resistance in parallel

B)To calculate strength of total current in each case:

1) To get minimum current, the two resistors should be connected in series.

Effective resistance for series connection: R= R1+R2

R=5+10

R=15Ω

By Ohm's law, we have V=IR

so, I=V/R

⇒6/15⇒0.4A

I=0.4A

2) To get maximum current, we should connect the resistance in parallel.

Effective resistance for parallel connection: 1/R=1/R1+1/R2

1/R=R1+R2/R1R2

∴R=R1R2/R1+R2

⇒5x10/5+10

⇒50/15⇒10/3Ω

By Ohm's law, we have V=IR

so, I=V/R

⇒(6/10)x3⇒1.8A

I=1.8A

Hope its clear