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Divide
x3 - 64 ; x-4
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Hope it will help you
Step-by-step explanation:
Factoring:x3-64
A difference of two perfect cubes, a3-b3 can be factored into
(a-b) (a2+ab+b2)
So,
(a-b) (a2+ab+b2) =a3+a2b+ab2-ba2-b2a-b3=a3+(a2b-ba2) +(ab2-b2a) - b3= a3+0+0+b3 = a3+b3.
64 is cube of 4
X3 is cube of x
Therefore factorisation is:
Ans -- (X-4) ; (x2+4x+16)
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