Math, asked by harshmalik7, 9 months ago

S Example 5: For a puja rupee 1 , rupees 2 and rupees 5 coins
are needed in the ratio 15:8:10. If the total
money value of these coins is 4050, find the
number of coins of each kind.

Answers

Answered by aritrashsarkar
0

Answer:750, 400, 250 respectively

Step-by-step explanation:

Coins needed: Re.1, Rs.2, Rs.5

Ratio given=15:8:10

Let the no. of coins be x, 2x and 5x.

Then, no. of Re.1 coins=15x

no. of Rs.2 coins=2x*8=16x

no. of Rs.5 coins=5x*10=50x

Total money collected= Rs. 4050

Therefore 15x + 16x + 50x = 4050

81x = 4050

x=50

No. of Re.1 coins=15 * 50 = 750

No. of Rs.2 coins=8 * 50 = 400

No. of Rs.5 coins=5 * 50 = 250

Answered by Angelsonam
2

Answer:

Let the no. of rs. one coin be 15x

no. of rs. two coin be 8x

no. of rs. five coin be 10x

A/Q

( 1×15x)+(2×8x)+(5×10x)=4050

15x+16x+50x=4050

81x=4050

x=4050÷81

Hence,x=50

So,no. of rs. one coin = 15x=15×50=750coins

no. of rs. two coin = 8x=8×50=400coins

no. of rs. five coin = 10x=10×50=500coins

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