Question

s factorisation metroal ?
a 3x
$3x ^{2} - 2 \sqrt{6x} + 2$

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Answer 1

3x²-2√6x+2=0

3x²-√6-√6x+2=0

√3×√3x²-√6x-√6x+√2×√2=0

√3x(√3x-√2)-√2( √3x-√2)=0

( √3x-√2)( √3x-√2)=0

hence ( √3x-√2) is the factor of 3x²-2√6x+2=0

and the value of x is-
( √3x-√2)=0

√3x=√2

x=√2/√3

hence,
x=
$\frac{ \sqrt{2} }{ \sqrt{3} }$

hope this helps.