Question

s-
factorise (x^-3x)^-8 (x^-3x) - 20​

Answer 1

Answer:

Put x^2-3x = y

Equation becomes y^2 -8 y-20

=> y^2-10y+2y-20

=> y(y-10)+2(y-10)

=> (y+2)(y-10)

now replace value of y from X

= (x^2-3x+2)(x^2-3x-10)

= (x^2-x-2x+2)(x^2+2x-5x-10)

= (x-1)(x-2)(x-5)(x+2)