Question

s Find the value for tan 90o, sin qe
taser 90° See 90°​

Answer 1

Derivation to Find the Value of Sin 90 Degrees

\sin x=\frac{1}{\csc x}

\sin^{2}x+\cos ^{2}x=1.

\sin (-x)=-\sin x.

Sin 2x = 2 sin x cos x.