Question

ғʀᴏᴍ ᴛʜᴇ sʏᴍʙᴏʟ ᴏғ
\frac{4}{2} x24​x
ɪᴅᴇɴᴛɪғʏ ᴛʜᴇ ᴇʟᴇᴍᴇɴᴛ ᴀɴᴅ ᴡʀɪᴛᴇ ᴅᴏᴡɴ ɪᴛs ᴍᴀss ɴᴜᴍʙᴇʀ ᴀɴᴅ ᴀᴛᴏᴍɪᴄ ɴᴜᴍʙᴇʀ.​

Answer 1

Answer:

$\huge\purple{\mid{\fbox{\tt{ANSWER࿐}}\mid}}$

ɪɴ ᴛʜᴇ sʏᴍʙᴏʟ ᴛʜᴇ ᴍᴀss ɴᴜᴍʙᴇʀ ɪs 4 ᴀɴᴅ ᴛʜᴇ ᴀᴛᴏᴍɪᴄ ɴᴜᴍʙᴇʀ ɪs 2, sᴏ ᴛʜᴇ sʏᴍʙᴏʟ ɪs ᴏғ ʜᴇʟɪᴜᴍ(ʜᴇ)

$\huge\underline{\overline{\mid{\bold{\pink{ɪᴛᴢᴍøøɴʙøʏ-}}\mid}}}$

Answer 2

Answer:

x2O

4

(l)

⟶2XO

2

(g)

The change in Gibb's free energy is given by

ΔG=ΔH−TΔS

whereas,

ΔH= Enthalpy of reaction

ΔS= Entropy of reaction =20cal/K

As we know that,

ΔH=ΔU+Δn

g

RT

whereas,

ΔU= Change in internal energy =2.1kcal=2100cal

Δn

g

=n

P

−n

R

=2−0=2

R= Gas constant =2cal

T=300K

∴ΔH=2100+(2×2×300)=3300cal

∴ΔG=3300−(300×20)=3300−600=2700=2.7kcal